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Question

An object is released from some height. Exactly after one second, another object is released from the same height. The distance between the two objects exactly after 2 seconds of the release of second object will be

A
4.9 m
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B
9.8 m
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C
19.6 m
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D
24.5 m
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Solution

The correct option is D 24.5 m
If time t=2 sec according to second object then total time elapsed by 1st particle =3 sec
Displacement of the respective particles are given by the formula
S=ut+12at2=12at2 [As u=0]
Thus, we have
S1=12×9.8×32
and, S2=12×9.8×22
Hence, distance between two objects is
S1S2=12×9.8(3222)=24.5 m

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