An object is thrown vertically upwards and rises to a height of 10 m. Calculate the time taken by the object to reach the highest point :

3.88 s

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2.87 s

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1.43 s

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1.01 s

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Solution

The correct option is C 1.43 s
In this case,
$v^{2} - u^{2} = 2 (- g) h$
when $h = h_{m a x}$ ;
$v = 0$
so, $u = \sqrt{2 \times g \times h}$
$u = 14$
For time $t$ ;
$v = u - g t$ ;
so, $t = 14 / 9.8$ = $14.3 m / s$

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An object is thrown vertically upwards and rises to a height of 10 m. Calculate the time taken by the object to reach the highest point :

The correct option is C 1.43 sIn this case, v2−u2=2(−g)hwhen h=hmax;v=0so, u=√2×g×hu=14For time t;v=u−gt;so, t=14/9.8 = 14.3m/s

The correct option is C 1.43 s
In this case,
$v^{2} - u^{2} = 2 (- g) h$
when $h = h_{m a x}$ ;
$v = 0$
so, $u = \sqrt{2 \times g \times h}$
$u = 14$
For time $t$ ;
$v = u - g t$ ;
so, $t = 14 / 9.8$ = $14.3 m / s$