An object mass 10 kg falls from rest through a vertical distance of 10 m and acquires a velocity of 10 m/s. The work done by the push of air on the object is (g=10m/s2).
Given that,
Mass of object, m=10Kg
Velocity, v=10m/s
Vertical distance, h=10m
From work energy theorem:
Work done by weight + work done by air = KE
Wair=KE−Wweight
=12mv2−mgh
=12×10×10×10−10×10×10
=−500J
The work done by the push of air on the object is -500 J.