    Question

# An object O is moving with velocity of (^i+2^j+3^k) m/s and a plane mirror in yz plane facing the object is moving with velocity of (2^i) m/s. The velocity of the image with respect to ground (in SI units) will be

A
2^i
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B
^i+2^j+3^k
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C
3^i+2^j+3^k
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D
2^i3^k
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Solution

## The correct option is C 3^i+2^j+3^k x - axis is the direction of normal of the plane mirror lying in yz - plane. Applying, (→vm)⊥=(→vo)⊥+(→vi)⊥2 ⇒(→vm)x=(→vo)x+(→vi)x2 ⇒2^i=1^i+(→vi)x2 ∴(→vi)x=3^i m/s Since, the mirror is lying along yz - plane, the y and z components of the velocity of the image will be the same as that of the object. ⇒(→vi)y=2^j m/s ⇒(→vi)z=3^k m/s Hence, the velocity of image w.r.t ground will be, →vi=(→vi)x+(→vi)y+(→vi)z ⇒→vi=(3^i+2^j+3^k) m/s  Suggest Corrections  1      Similar questions  Related Videos   Moving Object and Mirror
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