An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

8 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
6 cm

We have u = -8.0 cm, and f = +12 cm

Using $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ ,

$\frac{1}{v} = \frac{1}{12 c m} + \frac{1}{- 8.0 c m}$

or, $v = - 24 c m$ ,

Thus, $m = \frac{v}{u} = \frac{- 24 c m}{- 8.0 c m} = 3$

Thus, $h_{2} = 3 h_{1} = 3 \times 2.0 c m = 6.0 c m$ .

The positive sign shows that the image is erect.

Suggest Corrections

Similar questions

An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

Q. A

20 c m

tall object is placed perpendicular to the principal axis of a convex lens of focal length

10 c m

. If object distance is

15 c m

. Find the image distance.

An object is placed perpendicular to principal axis of a convex lens of focal length 20cm.the distance of object from lens is 30cm

Find the position,magn magnifica and Nature of image

Q. A 2 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of object from the lens is 15 cm. Find the position, nature and size of the image. Calculate the magnification of the lens.

Q. One half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens? Draw a ray diagram to justify your answer.
A 4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. Find the nature, position and size of the image.

Join BYJU'S Learning Program

An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

The correct option is C 6 cm We have u = -8.0 cm, and f = +12 cm Using 1v−1u=1f, 1v=112 cm+1−8.0 cm or, v=−24 cm, Thus, m=vu=−24 cm−8.0 cm=3 Thus, h2=3 h1=3×2.0 cm=6.0 cm. The positive sign shows that the image is erect.