An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

8 cm

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4 cm

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6 cm

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10 cm

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Solution

The correct option is C
6 cm

We have u = -8.0 cm, and f = +12 cm

Using $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ ,

$\frac{1}{v} = \frac{1}{12 c m} + \frac{1}{- 8.0 c m}$

or, $v = - 24 c m$ ,

Thus, $m = \frac{v}{u} = \frac{- 24 c m}{- 8.0 c m} = 3$

Thus, $h_{2} = 3 h_{1} = 3 \times 2.0 c m = 6.0 c m$ .

The positive sign shows that the image is erect.

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An object of length 2.0 cm is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. Find the size of the image if the object is at a distance of 8.0 cm from the lens.

The correct option is C 6 cm We have u = -8.0 cm, and f = +12 cm Using 1v−1u=1f, 1v=112 cm+1−8.0 cm or, v=−24 cm, Thus, m=vu=−24 cm−8.0 cm=3 Thus, h2=3 h1=3×2.0 cm=6.0 cm. The positive sign shows that the image is erect.