An object of mkg with a speed of vm/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be
A
2mvcosθ
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B
2mvsinθ
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C
0
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D
2mv
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Solution
The correct option is A2mvcosθ
Initial momentum −→P1=mvsinθ^i−mvcosθ^j and final momentum −→P2=mvsinθ^i+mvcosθ^j So change in momentum −−→ΔP=−→P2−−→P1=2mvcosθ^j |−−→ΔP|=2mvcosθ