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Question

An object of m kg with a speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be

A
2mvcosθ
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B
2mvsinθ
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C
0
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D
2mv
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Solution

The correct option is A 2mvcosθ

Initial momentum P1=mvsinθ^imvcosθ^j
and final momentum P2=mvsinθ^i+mvcosθ^j
So change in momentum
ΔP=P2P1=2mvcosθ^j
|ΔP|=2mvcosθ

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