An object of mass 1 kg moving on a horizontal surface with inital velocity 8m/s comes to rest after 10s. If one wants to keep the object moving on the same surface with velocity 8m/s the force required is ?

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Solution

apply the first equation of motion v=u+at
initial velocity =8m/s
final velocity =0
time =10 sec
acceleration = ?
v=u+at
0=8+10a
a=-0.8m/s^2
frictional force F= ma
mass =1 kg
acceleration = -0.8 m/s^2
1 x -0.8 =-0.8N
force required is 0.8 N

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An object of mass 1 kg moving on a horizontal surface with inital velocity 8m/s comes to rest after 10s. If one wants to keep the object moving on the same surface with velocity 8m/s the force required is ?

apply the first equation of motion v=u+at initial velocity =8m/s final velocity =0 time =10 sec acceleration = ? v=u+at 0=8+10a a=-0.8m/s^2 frictional force F= ma mass =1 kg acceleration = -0.8 m/s^2 1 x -0.8 =-0.8N force required is 0.8 N

apply the first equation of motion v=u+at
initial velocity =8m/s
final velocity =0
time =10 sec
acceleration = ?
v=u+at
0=8+10a
a=-0.8m/s^2
frictional force F= ma
mass =1 kg
acceleration = -0.8 m/s^2
1 x -0.8 =-0.8N
force required is 0.8 N