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Question

An object of mass 10 kg moves at a constant speed of 10m/s. A constant force that acts for 4 sec on the object gives it a speed of 2m/s in opposite direction. The force acting on the object is:

A
-3N
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B
-30N
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C
3N
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D
30N
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Solution

The correct option is A -30N
Force is equal to the rate change of momentum. i.e F=mdvdt
So, F=10×(2)104N=30N

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