An object starts 5m from origin and moves with an initial velocity of 5 $m s^{- 1}$ and has an acceleration of 2 $m s^{- 2}$ . After 10 sec, the object is how far from the origin?

150 m

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145 m

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155 m

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55 m

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Solution

The correct option is C 155 m
Displacement in $10 s e c o n d s$ is $u t + a t^{2} / 2$
$= 5 \times 10 + 2 \times 10^{2} / 2 = 150 m e t e r$
Final position is initial position+displacement $5 + 150 = 155 m e t e r$

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