Question 13
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

Open in App

Solution

(a) 2 N

According to Archimedes principle,
Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N

Suggest Corrections

Similar questions

An object weighs 10 N in air. When immersed fully in a liquid, it weighs only 8 N. The weight of liquid displaced by the object will be :
(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

Q. An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

Q. An object weighs

10 N

in air. When immersed fully in water, it weighs only

8 N

. The weight of the liquid displaced by the object will be :

An object weighs 10N in air. When immersed fully in a liquid, it weighs only 8N.The weight of a liquid displaced by object will be:

Q. The weight of an object in air is

16 N

. It weighs

12 N

when fully immersed in water. The weight of water displaced by the object is

Join BYJU'S Learning Program

Explore more

Archimedes' Principle

Standard IX Physics

Join BYJU'S Learning Program

Question 13 An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be (a) 2 N (b) 8 N (c) 10 N (d) 12 N​​​​​​​

(a) 2 N According to Archimedes principle, Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N

Question 13
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

(a) 2 N

According to Archimedes principle,
Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N