An object weighs $10 N$ in air. When immersed fully in water, it weighs only $8 N .$ The weight of the liquid displaced by the object will be:

2 N

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8 N

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10 N

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12 N

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Solution

The correct option is D $2 N$
According to Archimedes Principle "when a body is fully or partially immersed in a fluid at rest,it appears to lose weight.In other words,
Apparent weight $W^{'} = W - F_{b}$
where $F_{b}$ is buoyancy force which is equal to weight of displaced liquid.
Apparent weight $8 N = 10 N - F_{b}$
$F_{b} = 2 N$
or the weight of the liquid displaced by the object $2 N .$

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An object weighs 10N in air. When immersed fully in a liquid, it weighs only 8N.The weight of a liquid displaced by object will be:

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An object weighs 10N in air. When immersed fully in water, it weighs only 8N. The weight of the liquid displaced by the object will be:

An object weighs $10 N$ in air. When immersed fully in water, it weighs only $8 N .$ The weight of the liquid displaced by the object will be: