An objects of mass 40kg having velocity 4- m-s collides with another object of mass 60kg having velocity 2- m-s- If collision is pefectly inelastic- then the loss of mechanical energy is

The correct option is C 48J m_1v_1+m_2v_2 = (m_1+m_2)v 40× 4+60× 2 = 100 × v 160 +120 = 100× v v = 2.8 m/s #160;K.E belong collision ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Velocity of COM

An objects of...

Question

An objects of mass $40 k g$ having velocity $4^i m / s$ collides with another object of mass $60 k g$ having velocity $2^i m / s$ . If collision is pefectly inelastic, then the loss of mechanical energy is

24 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

96 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

48 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $48 J$
$m_{1} v_{1} + m_{2} v_{2} = (m_{1} + m_{2}) v$
$40 \times 4 + 60 \times 2 = 100 \times v$
$160 + 120 = 100 \times v$
$v = 2.8 m / s$
K.E belong collision $= \frac{1}{2} m_{1} v_{1}^{2} + \frac{1}{2} m_{2} v_{2}^{2}$
$= 320 + 120 = 440 J$
K.E after collision $= \frac{1}{2} (m_{1} + m_{2}) v^{2} = \frac{1}{2} \times 100 \times {2.8}^{2}$
Loss $= 440 - 392 - 48 J = 392 J$

Suggest Corrections

Similar questions

Q. An object of mass

40 k g

having velocity

4 m / s

collides with another object of mass

60 k g

having velocity

2 m / s

. The collision is perfectly inelastic. The loss in energy is:

Q. A body of mass

40 k g

having velocity 4 m/s collides with another body of mass

60 k g

having velocity 2 the collision is inelastic then loss in kinetic energy will be

A body of mass 40 kg having velocity 4 m/s collides with another body of mass 60 kg having velocity 2 m/s. If the collision is inelastic, then loss in kinetic energy will be

Q. An object of mass 0.4 kg moving with velocity of 4 m/s collides with another object of same mass moving in same direction with velocity of 2 m/s. If the collision is perfectly inelastic (plastic), then what will be the loss of K. E due to impact?

Join BYJU'S Learning Program

An objects of mass 40kg having velocity 4^im/s collides with another object of mass 60kg having velocity 2^im/s. If collision is pefectly inelastic, then the loss of mechanical energy is

The correct option is C 48Jm1v1+m2v2=(m1+m2)v40×4+60×2=100×v160+120=100×vv=2.8m/s K.E belong collision =12m1v21+12m2v22=320+120=440JK.E after collision =12(m1+m2)v2=12×100×2.82 Loss =440−392−48J=392J

An objects of mass $40 k g$ having velocity $4^i m / s$ collides with another object of mass $60 k g$ having velocity $2^i m / s$ . If collision is pefectly inelastic, then the loss of mechanical energy is