An Olympic swimming pool is in the shape of a cuboid of dimensions 50 m. long and 25 m. wide. If it is 3 m. deep throughout, how many liters of water does it hold? (1 cu.m = 1000 liters)

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Solution

Volume of the cuboidal swimming pool = length $\times$ width $\times$ depth
$= 50 m \times 25 m \times 3 m$
$= 3750 m^{3}$
$1 m^{3} = 1000$ litres
So, Amount of water that the swimming pool holds $= 3750 \times 1000$ litres
$= 3750000$ litres

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An Olympic swimming pool is in the shape of a cuboid of dimensions 50 m. long and 25 m. wide. If it is 3 m. deep throughout, how many liters of water does it hold? (1 cu.m = 1000 liters)

Volume of the cuboidal swimming pool = length×width×depth =50 m×25 m×3 m =3750 m3 1 m3=1000 litres So, Amount of water that the swimming pool holds =3750×1000 litres =3750000 litres

Volume of the cuboidal swimming pool = length $\times$ width $\times$ depth
$= 50 m \times 25 m \times 3 m$
$= 3750 m^{3}$
$1 m^{3} = 1000$ litres
So, Amount of water that the swimming pool holds $= 3750 \times 1000$ litres
$= 3750000$ litres