An open pipe is suddenly closed with the result that, the second overtone on the closed pipe is found to be higher in frequency by 100Hz, then the first overtone of the original pipe. the fundamental frequency of open pipe will be:
A
100Hz
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B
300Hz
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C
150Hz
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D
200Hz
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Solution
The correct option is B200Hz Let L be the length of pipe.
frequency of first overtone, when the pipe is open ,
n2=v/L ,
frequency of second overtone , when the pipe is closed ,
n′3=5v/4L ,
given , n2+100=n′3 ,
or v/L+100=5v/4L ,
or v/4l=100 ,
or l=v/400 ,
therefore fundamental frequency of open pipe will be ,