Question

An open rectangular tank $4m$ long and $2.5m$ wide contains an oil of specific gravity $0.85$ up to a depth of $1.5m$. Determine the total pressure on the bottom of the tank(per unit area), when the tank is moving with an acceleration of $\frac{g}{2}$ $m{s}^{-2}$ vertically upward.

• A. $15.765KN{m}^{-2}$
• B. $12.665KN{m}^{-2}$
• C. $18.765KN{m}^{-2}$
• D. $28.765KN{m}^{-2}$

Answer 1

The correct option is C $18.765KN{m}^{-2}$

Due to acceleration $a$ upwards, the pressure at the bottom of the tank $=\rho (g+a)h=\frac{3}{2}\rho gh$

Hence, the pressure at the bottom of tank is:

$P_{bottom}=\frac{3}{2}\times 0.85\times 1000\times \times 9.8\times 1.5$

$=18765N/m^2$

$=18.765kN/m^2$