Question

An open vessel at ${27}^{\circ }C$ is heated until three-fifth of the air in it has been expelled. Assuming that the volume of the vessel remains constant, find the temperature to which the vessel has been heated?

Answer 1

Both volume and pressure are constant as the vessel is open, the product of $PV$ is constant.

i.e., $n_{1}R{T}_1=n_{2}R{T}_2$

or $\frac{n_1}{n_2}=\frac{T_2}{T_1}$

If $n_1=1,n_2=1-\frac{3}{5}=\frac{2}{5}$

So, $\frac{5}{2}=\frac{T_2}{300}$ or $T_2=750Kor{477}^{\circ }C$