1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# An open vessel at 27oC is heated until 38th of the air in it has been expelled. Assuming that the volume remains constant, calculate the temperature to which the vessel was heated.

A
307oC
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
107oC
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
480oC
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
207oC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 207oCPV=nRT at constant temperature and pressure , nT is constant Given, Initial temperature T1=27oC=27+273=300 K initial moles = n1 final moles = n1−3n18=5n18 Using n1T1=n2T2,T2=n1n2T1=n(1−3/8)n×300=n(5/8)n×300=480 K. ∴T2=207oC.

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
The Ideal Gas Equation
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program