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Question

An ordinary mercury thermometer is first put in a beaker containing dry ice and is then transferred into another beaker containing dry ice and is then transferred into another beaker containing hot water. The mercury thread rises four-fifth of the distance between the lower and upper fixed points. Find the temperature of water in
(1) in degree Celsius, and (2) in degree Fahrenheit.

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Solution

The lower fixed point = 00C

The upper fixed point = 1000C

Difference between lower and upper fixed point = 1000C – 00C = 1000C

The temperature of the liquid = 4/5×1000C

= 800 C

In Kelvin = 80 + 273 = 353 K

F = 9/5 × C + 32 = 176 0F


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