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Byju's Answer
Standard X
Chemistry
Addition of Sulphuric Acid and Water
An organic co...
Question
An organic compound 'A' having molecular formula C
3
H
6
on treated with aqueous H
2
SO
4
gives 'B' which on treated with HCl/ZnC1
2
gives 'C'. The compound C on treatment with ethanolic KOH gives back the compound 'A'. Identify the compounds A, B and C.
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Solution
Dear Student,
A
h
y
d
r
o
c
a
r
b
o
n
o
f
f
o
r
m
u
l
a
C
3
H
6
o
n
h
y
d
r
a
t
i
o
n
w
i
t
h
s
u
l
p
h
u
r
i
c
a
c
i
d
g
i
v
e
s
B
.
S
o
A
i
s
a
n
a
l
k
e
n
e
w
i
t
h
g
e
n
e
r
a
l
f
o
r
m
u
l
a
C
n
H
2
n
a
n
d
i
t
g
i
v
e
s
a
l
c
o
h
o
l
B
.
A
l
c
o
h
o
l
B
r
e
a
c
t
s
w
i
t
h
A
n
h
y
Z
n
C
l
2
a
n
d
C
o
n
H
C
l
(
l
u
c
a
s
r
e
a
g
e
n
t
)
t
o
g
i
v
e
h
a
l
o
a
l
k
a
n
e
.
W
h
i
c
h
r
e
a
c
t
s
w
i
t
h
s
o
d
i
u
m
e
t
h
o
x
i
d
e
t
o
g
i
v
e
a
n
a
l
k
e
n
e
b
a
c
k
.
C
H
3
C
H
=
C
H
2
→
H
g
2
+
d
i
l
H
2
S
O
4
C
H
3
C
H
(
O
H
)
-
C
H
3
→
a
n
h
y
Z
n
C
l
2
C
o
n
H
C
l
C
H
3
C
H
(
C
l
)
-
C
H
3
→
C
2
H
5
O
N
a
C
H
3
C
H
(
O
C
2
H
5
)
-
C
H
3
+
N
a
C
l
A
B
C
C
H
3
C
H
(
O
C
2
H
5
)
-
C
H
3
→
∆
C
H
3
C
H
=
C
H
2
+
C
2
H
5
O
H
T
h
u
s
A
=
1
-
p
r
o
p
e
n
e
B
=
2
-
p
r
o
p
a
n
o
l
C
=
2
-
c
h
l
o
r
o
p
r
o
p
a
n
e
Regards,
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