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Question

An organic compound 'A' having molecular formula C3H6 on treated with aqueous H2SO4 gives 'B' which on treated with HCl/ZnC12 gives 'C'. The compound C on treatment with ethanolic KOH gives back the compound 'A'. Identify the compounds A, B and C.

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Solution

Dear Student,

A hydrocarbon of formulaC3H6 on hydration with sulphuric acid gives B. So A is an alkene with general formula CnH2n and it gives alcohol B. Alcohol Breacts with Anhy ZnCl2 and Con HCl (lucas reagent) to give haloalkane. Which reacts withsodium ethoxide to give an alkene back.CH3CH=CH2 Hg2+dil H2SO4 CH3CH(OH)-CH3 anhy ZnCl2Con HCl CH3CH(Cl)-CH3 C2H5ONa CH3CH(OC2H5)-CH3 + NaCl A B C CH3CH(OC2H5)-CH3 CH3CH=CH2 + C2H5OHThus A = 1-propeneB= 2 -propanolC =2-chloropropane

Regards,

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