An organic compound ′A′ on treatment with NH3 gives ′B′ which on heating gives ′C′, ′C′ when treated with Br2 in the presence of KOH produces ethylamine. Compound ′A′ is:
A
CH3COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
CH3CH2CH2COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
CH3−CH|CH3COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
CH3CH2COOH
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DCH3CH2COOH The compound A is propionic acid CH3CH2COOH. Propionic aicd reacts with ammonia to form ammonium propionate. On heating, ammonium propionate is converted to propionamid. Hoffmann bromamide reaction in presence of KOH and bromine converts propionamide to ethyl amine. In this process, one carbon atom is lost. CH3−CH2−COOHNH3−−−→CH3−CH2−CO¯O+NH4Δ−→CH3−CH2−CONH2KOH+Br2−−−−−−−→CH3−CH2−NH2 (A) (B) (C)