An organic compound (A) with the molecular formula, $(C_{7} H_{8} O)$ dissolves in $N a O H$ and gives characteristics colour with neutral $F e C l_{3}$ . On treatment with bromine water, it gives a tribromo derivative, $C_{7} H_{5} O B r_{3}$ . The compound is:

p-cresol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

o-cresol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m-cresol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

benzyl alcohol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C m-cresol
Reactivity of compound ‘A’ with $N a O H$ and $F e C l_{3}$ suggests (A) to be a phenol. The formation of a tribromo product suggests that $o -$ & $p -$ positions are vacant. So the $- C H_{3}$ group should be present at m-positons. Hence (A) is m-cresol.

Suggest Corrections

Similar questions

An organic compound A (molecular formula $C_{2} H_{4} O_{2})$ reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula $C_{2} H_{6} O_{2})$ . Compound D on treatment with NaOH solution gives back B and C. Indentity A, B, C and D.

Q. An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.

Q. An organic compound (A) with molecular formula

C_{7} H_{8} O

dissolves in NaOH and gives characteristic colour with

F e C l_{3} .

On treatment with

B r_{2},

it gives a tribromo product

C_{7} H_{5} O B r_{3} .

The compound is :

Q. An organic compound (A) of molecular formula

C_{7} H_{8} O

on treatment with lead nitrate gives a compound (B) of molecular formula

C_{7} H_{6} O

. (B) on chlorination in presence of

F e C l_{3}

form compound (C). Identify A, B and C, write the reactions.

The structure of the compound that gives a tribromo derivative with bromine water is:

Join BYJU'S Learning Program

An organic compound (A) with the molecular formula, (C7H8O) dissolves in NaOH and gives characteristics colour with neutral FeCl3. On treatment with bromine water, it gives a tribromo derivative, C7H5OBr3. The compound is:

The correct option is C m-cresolReactivity of compound ‘A’ with NaOH and FeCl3 suggests (A) to be a phenol. The formation of a tribromo product suggests that o− & p− positions are vacant. So the –CH3 group should be present at m-positons. Hence (A) is m-cresol.

An organic compound (A) with the molecular formula, $(C_{7} H_{8} O)$ dissolves in $N a O H$ and gives characteristics colour with neutral $F e C l_{3}$ . On treatment with bromine water, it gives a tribromo derivative, $C_{7} H_{5} O B r_{3}$ . The compound is:

The correct option is C m-cresol
Reactivity of compound ‘A’ with $N a O H$ and $F e C l_{3}$ suggests (A) to be a phenol. The formation of a tribromo product suggests that $o -$ & $p -$ positions are vacant. So the $- C H_{3}$ group should be present at m-positons. Hence (A) is m-cresol.