An organic compound contains $40.65$ % carbon, $8.55$ % hydrogen and $23.77$ % nitrogen. Its vapour density is $29.5$ . Find its molecular formula.

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Solution

Molecular mass $= 2 \times V a p o r d e n s i t y = 59 g m o l^{- 1}$
% $C = 40.65 \Rightarrow \frac{59 \times 40.65}{100} = 24 g / m o l e s = \frac{24}{12} = 2 m o l e s$
% $H = 8.55 \Rightarrow \frac{59 \times 8.55}{100} = 5 g / m o l e s = \frac{5}{1} = 5 m o l e s$
% $N = 23.77 \Rightarrow \frac{59 \times 23.77}{100} = 14 g / m o l e s = \frac{14}{14} = 1 m o l e s$
Mass of oxygen $= 59 - 43 = 16 g / m o l e s = 1$
Molecular formula is $C_{2} H_{5} N O$

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An organic compound contains 40.65% carbon, 8.55% hydrogen and 23.77% nitrogen. Its vapour density is 29.5. Find its molecular formula.

Molecular mass =2×Vapor density=59 g mol−1% C=40.65⇒59×40.65100=24 g/moles=2412=2 moles% H=8.55⇒59×8.55100=5 g/moles=51=5 moles% N=23.77⇒59×23.77100=14 g/moles=1414=1 molesMass of oxygen =59−43=16 g/moles=1Molecular formula is C2H5NO

An organic compound contains $40.65$ % carbon, $8.55$ % hydrogen and $23.77$ % nitrogen. Its vapour density is $29.5$ . Find its molecular formula.