Question

An organic compound contains $62\%$ carbon, $27.6\%$ oxygen and $10.4\%$ hydrogen, its empirical formula is

Answer 1

Answer (3)
$\begin{array}{ccccc}\text{Element}& \text{percentage}& \text{No. of moles}& \text{Simple Ratio}& \text{Simplest whole number ratio}\\ \text{C}& 62& \frac{62}{12}=5.16& \frac{5.16}{1.725}=2.99& 3\\ \text{O}& 27.6& \frac{27.6}{16}=1.725& \frac{1.725}{1725}=1& 1\\ \text{H}& 10.4& \frac{10.4}{1}=10.4& \frac{10.4}{1.725}=6.02& 6\end{array}$
The empirical formula of compound is $C_3{H}_{6}O.$