An organic compound contains $75 %$ carbon and $25 %$ hydrogen. The empirical formula of the compound would be:

C H_{4}

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C H

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C_{2} H_{3}

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C H_{2}

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Solution

The correct option is A $C H_{4}$
For calculating the empirical formula,

$\begin{matrix} Element & % in compound & Atomic mass & No. of moles & Simple ratio C & 75 & 12 & \frac{75}{12} = 6.25 & \frac{6.25}{6.25} = 1 H & 25 & 1 & \frac{25}{1} = 25 & \frac{25}{6.25} = 4 \end{matrix}$

So, the empirical formula is $C H_{4}$

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