An organic compound contains 90% carbon and 10% hydrogen by mass. Its empirical formula is:

C_{2} H_{4}

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C_{3} H_{6}

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C_{2} H_{6}

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C_{3} H_{4}

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Solution

The correct option is D $C_{3} H_{4}$
Let us take the mass of compound $= 100 g m$

Moles of carbon $= \frac{90}{12} = 7.5$

Moles of hydrogen $= \frac{10}{1} = 10$

The ratio of $C : H = 7.5 : 10$

$= 3 : 4$

$∴$ Empirical formula $= C_{3} H_{4}$ .

Hence, option D is correct.

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An organic compound contains 90% carbon and 10% hydrogen by mass. Its empirical formula is:

The correct option is D C3H4Let us take the mass of compound =100 gmMoles of carbon =9012=7.5Moles of hydrogen =101=10The ratio of C:H=7.5:10 =3:4∴ Empirical formula =C3H4.Hence, option D is correct.

The correct option is D $C_{3} H_{4}$
Let us take the mass of compound $= 100 g m$

Moles of carbon $= \frac{90}{12} = 7.5$

Moles of hydrogen $= \frac{10}{1} = 10$

The ratio of $C : H = 7.5 : 10$

$= 3 : 4$

$∴$ Empirical formula $= C_{3} H_{4}$ .

Hence, option D is correct.