An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral center is not the sufficient criterion for optical activity. The ultimate criterion is presence or absence of either plane or center of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereoisomers of the compounds. Those words are diastereomers and mesomers.
Optically active compounds among the following is/are
(A) CH3−CH=C=CH2
(B) CH3−CH=C=CH−CH3
An organic compound having a carbon attached to four different groups is optically active. But, is the opposite also true? That is, do all optically active organic compounds have chiral carbons? Not necessarily. Presence or absence of chiral center is not the sufficient criterion for optical activity. The ultimate criterion is presence or absence of either plane or center of symmetry. Two compounds which are non-superimposable mirror images of each other are called enantiomers. If a compound contains more than one chiral carbon, new words are required to describe the relationship between various stereoisomers of the compounds. Those words are diastereomers and mesomers.
Optically active compounds among the following is/are
(A) CH3−CH=C=CH2
(B) CH3−CH=C=CH−CH3
The correct option is C B, C, and E
A) The compound is symmetric. So, not chiral.
D) Compound has center of symmetry so not chiral.
B, C, E are chiral and optically active.
A) The compound is symmetric. So, not chiral.
D) Compound has center of symmetry so not chiral.
B, C, E are chiral and optically active.
