Question

An organic compund contains $C=40\%,H=13.33\%$ and $N=46.67\%$. Its emperical formula is :

• A. $C_2{H}_{2}N$
• B. $C_3{H}_{7}N$
• C. $C{H}_{4}N$
• D. $CHN$

Answer 1

The correct option is C $C{H}_{4}N$

Consider the compound to be made of 100g. Convert percentile to weight in grams. then, convert wt. in grams to moles.

Moles of $C=40/12=3.33$

Moles of $H=13.33/1=13.33$

Moles of $N=46.6/14=3.33$

Now divide each mole value by lowest value of n as:

$C=3.33/3.33=1$

$H=13.33/3.33=4.00$

$N=3.33/3.33=1$

The emperical formula is $C{H}_{4}N$.