An oxide of iodine contains 25.4 g of iodine for 8 g of oxygen. Its molecular formula will be:

I_{2} O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{2} O_{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I_{2} O_{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I_{2} O_{5}$
Element Mass Mole ratio Simple ratio
Iodine $25.4$ $\frac{25.4}{127} = 0.2$ $2$
Oxygen $8$ $\frac{8}{16} = 0.5$ $5$
Hence option C is correct.

Suggest Corrections

Similar questions

I = 127

25.4

8

3.34 g

(l = 127)

25.4 g

8 g

254

80

Join BYJU'S Learning Program