On analysis, a certain compound was found to contain $254$ g of iodine and $80$ g of oxygen. The formula of the compound is:

I O

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I_{2} O

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I_{5} O_{3}

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I_{2} O_{5}

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Solution

The correct option is D $I_{2} O_{5}$
Atomic weight of iodine $= 127$ g.
Atomic weight of oxygen $= 16$ g.
Ratio of the number of gram atoms between $I$ and $O$ ,
$I : O = \frac{254}{127} : \frac{80}{16} = 2 : 5$
Therefore, the empirical formula is $I_{2} O_{5}$ .

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On analysis, a certain compound was found to contain 254 g of iodine and 80 g of oxygen. The formula of the compound is:

The correct option is D I2O5Atomic weight of iodine =127 g. Atomic weight of oxygen =16 g.Ratio of the number of gram atoms between I and O,I:O=254127:8016=2:5Therefore, the empirical formula is I2O5.

On analysis, a certain compound was found to contain $254$ g of iodine and $80$ g of oxygen. The formula of the compound is:

The correct option is D $I_{2} O_{5}$
Atomic weight of iodine $= 127$ g.
Atomic weight of oxygen $= 16$ g.
Ratio of the number of gram atoms between $I$ and $O$ ,
$I : O = \frac{254}{127} : \frac{80}{16} = 2 : 5$
Therefore, the empirical formula is $I_{2} O_{5}$ .