Question

On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254:80. The formula of the compound is:

[Atomic mass: I =127, O =16]

• A. $IO$
• B. $I_{2}O$
• C. $I_5{O}_2$
• D. $I_2{O}_5$

Answer 1

The correct option is D $I_2{O}_5$

A compound containing iodine and oxygen in the ratio of 254:80

$\therefore$ No of moles of Iodine atoms $\left(I\right)=\frac{254}{127}=2$

Number of moles of oxygen atoms $\left(O\right)=\frac{80}{16}=5$

Therefore the formula is $I_2{O}_5$.