Question

An oxide of lead changes to another insoluble oxide and soluble salt on reaction with $HN{O}_3$
(a) What is Oxide ?.
(b) What is insoluble oxide ?.
(c) What is soluble salt ?.

• A. (a)$P{b}_3{O}_4$; (b)$Pb{O}_3$; (c)$Pb(N{O}_3{)}_2$
• B. (a)$P{b}_3{O}_3$; (b)$Pb{O}_2$; (c)$Pb(N{O}_3{)}_3$
• C. (a)$P{b}_3{O}_4$; (b)$Pb{O}_2$; (c)$Pb(N{O}_3{)}_2$
• D. (a)$P{b}_3{O}_4$; (b)$Pb{O}_4$; (c)$Pb(N{O}_3{)}_3$

Answer 1

Answer: (C)

(a)$P{b}_3{O}_4$; (b)$Pb{O}_2$; (c)$Pb(N{O}_3{)}_2$

Given that an oxide of lead changes to another insoluble oxide and soluble salt on reaction with $HN{O}_3$.

The reaction is as follows:

$P{b}_3{O}_4+HN{O}_3\to Pb(N{O}_3{)}_2+Pb{O}_2+H_{2}O$

The lead oxide $\left(a\right)$ is $P{b}_3{O}_4$ which is non-polar and insoluble in water, changes to another insoluble oxide $\left(b\right)$ $Pb{O}_2$ and soluble salt $\left(c\right)Pb(N{O}_3{)}_2$ on reaction with $HN{O}_3$.