Question

An oxide of sulphur contain 50% S .Empirical formula of oxide will be

Answer 1

Dear Student,

$$\begin{gathered} \%\mathrm{of}\mathrm{S}=50 \\ \mathrm{So},\%\mathrm{of}\mathrm{O}=50 \\ \mathrm{Therefore},50\mathrm{g}\mathrm{of}\mathrm{S}\mathrm{and}\mathrm{O}\mathrm{are}\mathrm{present}. \\ \mathrm{Moles}\mathrm{of}\mathrm{S}=\frac{50}{32}=1.5625 \\ \mathrm{Moles}\mathrm{of}\mathrm{O}=\frac{50}{16}=3.125 \\ \mathrm{Divind}\mathrm{both}\mathrm{by}\mathrm{smaller}\mathrm{one} \\ \mathrm{S}=\frac{1.5625}{1.5625}=1 \\ \mathrm{O}=\frac{3.125}{1.5625}=2 \\ \mathrm{So},\mathrm{empirical}\mathrm{formula}={\mathrm{SO}}_2 \end{gathered}$$