An unbiased dice is thrown two times having first six consecutive odd numbers on each six faces Find the probability of getting even sum

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\frac{1}{36}

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\frac{4}{36}

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Solution

The correct option is A 1
$A l l t h e 6 s i d e s a r e o d d n o s . S u m o f t w o o d d n o s i s a l w a y s e v e n . S o w h e n w e t h r o w t h e d i c e t w o t i m e s, w e w i l l a l w a y s g e t a n e v e n n o . S o p r o b a b i l i t y = 1$

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