Question

An unbiased die is thrown, then the probability of getting an even number and a multiple of 3 is ____.

• A. 5/6
• B. 1/3
• C. 1/6
• D. 2/3

Answer 1

The correct option is C 1/6

Let A denote the event “getting an even number and a multiple of 3”
Clearly, event A happens if we get 6 as an outcome.
$\therefore$ Favourable number of outcomes is 1 out of 6.
Hence, the probability of getting an even number and a multiple of 3 is $P\left(A\right)=\frac{totalnumberoffavourableoutcomes}{totalnumberofoutcomes}=\frac{1}{6}.$