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Question

An unbiased die is thrown, what is the probability of getting
(i) an even number of a multiple of 3
(ii) a number 3 or 4
(iii) a number greater than 3

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Solution

In a single throw of a dice, we get 1,2,3,4,5 or 6.
Number of total outcomes n(S)=6
Probability of an event(A) is
P(A)=Number of favourable outcomesTotal number of outcomes=n(A)n(S), Where S is sample space.

(i) Even numbers multiple of 3 are 3,6

Favourable no. of outcomes n(A)=2
Required probability P(A)=26
P(A)=13

(ii) a number 3 or 4

Favourable no. of outcomes n(A)=2
P(A)=26
P(A)=13

(iii) number greater than 3 are 4,5,6

Favourable no. of outcomes n(A)=3
P(A)=36
P(A)=12


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