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Question

An unbiased die is tossed twice. Find the probability of getting 4, 5, or 6 on the first toss and 1, 2, 3 or 4 on the second toss.

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Solution

PA=P4, 5 or 6 on first toss=1836=12PB=P1, 2, 3 or 4 on second toss=2436=23It is clear that A and B are independent events.PAB=PAPBPAB=12×23 PAB=13

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