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Question

An die is tossed twice. Find the probability of getting 4,5 or 6 on the toss and 1,2,3 or 4 on the second toss.

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Solution

Total possible outcomes 6

Favorable outcomes for first event 4,5,6

Probability of first event 36=12

Favorable outcomes for second event 1,2,3,4

Probability of first event 46=23

The events are independant

So Required proabability is 12×23=13


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