Question

An uncharged capacitor of capacitance 'C' is charged by cell of $E.M.F(\in )$. The ratio of work done by cell during charging & energy stored is

• A. 1:1
• B. 1:3
• C. 1:2
• D. 2:1

Answer 1

The correct option is D 2:1


Work done by cell =q.e
$=Cϵ.ϵ=C{ϵ}^2$
Energy stored $=\frac{1}{2}C{ϵ}^2$
Work: Energy $=C{ϵ}^2:\frac{1}{2}C{ϵ}^2=2:1$