An underwater sonar source operating at a frequency of 60kHz directs its beamtowards the surface. If the velocity of sound in air is 330m/s, the wavelength and frequency of waves in air are:
A
5.5mm,60kHz
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B
330m,60kHz
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C
5.5mm,20kHz
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D
5.5mm,80kHz
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Solution
The correct option is A5.5mm,60kHz
Given,
Frequency, f=60kHz=6×104Hz
Velocity of sound in air, v=330m/s
Wavelength, λ
We know,
λ=vf
λ=33060×103
λ=5.5×10−3m
λ=5.5mm
The frequency is a characteristic of the source. It does not change on the medium.