Question

An ungraduated thermometer of uniform bore is attached to a centimeter scale and is found to read $10cm$ in melting ice, $30cm$ in boiling water and $16cm$ in a liquid. Find temperature of the liquid.

Answer 1

Temperature at 10 cm is $0^{0}C$.

Temperature at $30cm$ si ${100}^{0}C$.

So at L=16 cm, let say it measure T.

So

$\frac{L-10}{30-10}=\frac{T-0}{100-0}$

$\frac{16-10}{30-10}=\frac{T-0}{100-0}$

$T={30}^{0}C$