Question

An urn contain 20 tickets numbered 1 to 20. A ticket is drawn and then another ticket is drawn without replacement. The probability that both the tickets show odd number is.......

• A. 9/38
• B. 1/8
• C. 1/4
• D. 5/8

Answer 1

The correct option is A 9/38

Given: an urn containing 20 tickets, and 2 tickets are drawn without replacement

To find: the probability that both the tickets show odd number

Sol: According to the question

$n\left(S\right)=20$

There are 10 odd numbers between 1 to 20.

Therefore, the probability that both the tickets show odd number is

$=\frac{10}{20}\times \frac{9}{19}=\frac{9}{38}$