Question

An urn contain $20$ tickets numbered $1$ to $20$. A ticket is drawn and then another ticket is drawn without replacement. The probability that both the tickets show even number is:

• A. $\frac{9}{38}$
• B. $\frac{1}{8}$
• C. $\frac{1}{4}$
• D. $\frac{5}{8}$

Answer 1

Answer: (A)

$\frac{9}{38}$

Given: an urn containing $20$ tickets, and $2$ tickets are drawn without replacement

To find: the probability that both the tickets show even number

According to the question

$n\left(S\right)=20$

There are $10$ even numbers between $1$ to $20$.

Therefore, the probability that both the tickets show even number is

$=\frac{10}{20}\times \frac{9}{19}=\frac{9}{38}$