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An urn contai...

Question

An urn contains 6 red, 4 blue and 3 green marbles. If 2 marbles are picked at random, then what is the probability that both the marbles are red?

21/26

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5/26

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10/13

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3/13

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None of these

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Solution

The correct option is B
5/26

P(E) = $\frac{^{6} C_{2}}{^{13} C_{2}}$ = $\frac{5}{26}$ .

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An urn contains 6 red, 4 blue and 3 green marbles. If 2 marbles are picked at random, then what is the probability that both the marbles are red?

The correct option is B 5/26 P(E) = 6C213C2 = 526.

The correct option is B
5/26

P(E) = $\frac{^{6} C_{2}}{^{13} C_{2}}$ = $\frac{5}{26}$ .