An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33 angstrom. What is the maximum energy of a photon in the radiation? Given Planck's constant $= 6.6 \times 10^{- 34} J s$ .

35 keV

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37.5 keV

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40 keV

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42.5 keV

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Solution

The correct option is B 37.5 keV
We know that, $E_{m a x} = \frac{h c}{λ_{m i n}} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{0.33 \times 10^{- 10}} = 6 \times 10^{- 15} J = 37.5 k e V$
Hence, the correct choice is (b).

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Similar questions

Q. An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33 angstrom. What is the maximum energy of a photon in the radiation? Given Planck's constant

= 6.6 \times 10^{- 34} J s

(a) An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.45 Å. What is the maximum energy of a photon in the radiation?

(b) From your answer to (a), guess what order of accelerating voltage (for electrons) is required in such a tube?

Q. An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of

45 \times 10^{- 2} A^{0}

. The maximum energy of photon in the radiation is

Q. An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.40

A^{0}

. Then the maximum energy of the photon of the emitted radiation.

(

h = 6.63 \times 10^{- 34} J s

and

c = 3 \times 10^{8}

m/s)

Q. (a) An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.45 . What is the maximum energy of a photon in the radiation?

(b) From your answer to (a), guess what order of accelerating voltage(for electrons) is required in such a tube?

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An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33 angstrom. What is the maximum energy of a photon in the radiation? Given Planck's constant =6.6×10−34 Js.

The correct option is B 37.5 keVWe know that, Emax=hcλmin=6.6×10−34×3×1080.33×10−10=6×10−15 J=37.5 keV Hence, the correct choice is (b).

An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33 angstrom. What is the maximum energy of a photon in the radiation? Given Planck's constant $= 6.6 \times 10^{- 34} J s$ .

The correct option is B 37.5 keV
We know that, $E_{m a x} = \frac{h c}{λ_{m i n}} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{0.33 \times 10^{- 10}} = 6 \times 10^{- 15} J = 37.5 k e V$
Hence, the correct choice is (b).