Question

An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45\times {10}^{-2}{A}^0$. The maximum energy of photon in the radiation is

• A. $2.77\times {10}^{4}eV$
• B. $1.64\times {10}^{4}eV$
• C. $3.8\times {10}^{4}eV$
• D. $4.7\times {10}^{4}eV$

Answer 1

Answer: (A)

$2.77\times {10}^{4}eV$

${\lambda }_{cutoff}=\frac{hc}{E_{max}}$

$E_{max}=\frac{hc}{{\lambda }_{cutoff}}$

$=2.77\times {10}^{4}eV$

So, the answer is option (A).