Question

An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45\times {10}^{-2}$ $A^0$. The maximum energy photon in the radiation in eV is.

($h=6.62\times {10}^{-34}Js$, $C=3\times {10}^8$ m/sec.)

• A. 27,500
• B. 22,500
• C. 17,500
• D. 12,500

Answer 1

Answer: (A)

27,500

$Maximumenergy=\frac{hc}{\lambda }$

=$\frac{1240eV-nm}{45\times {10}^{-3}nm}$ (hc = 1240 eV-nm)

=$27.5\times {10}^{3}eV$
=27500 eV.
So, the answer is option (A).