Question

$\angle A$ and $\angle B$ are supplementary angles. $\angle A=x+{10}^o$ and $\angle B=x-{10}^o$, find $\angle A$ and $\angle B$

Answer 1

$\angle A=x+{10}^{\circ },\angle B=x-{10}^{\circ }$

Given $\angle A$ and $\angle B$ are supplementary angles

$⟹x+{10}^{\circ }+x-{10}^{\circ }={180}^{\circ }⟹x={90}^{\circ }$

$\angle A={90}^{\circ }+{10}^{\circ }={100}^{\circ }$

$\angle B={90}^{\circ }-{10}^{\circ }={80}^{\circ }$