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Byju's Answer
Standard XII
Physics
Direction of Friction
Angle θ is ...
Question
Angle
θ
is gradually increased as shown in figure. For the given situation match the following two columns. (g =
10
m
s
−
2
)
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Solution
Normal force on the block is
N
=
m
g
c
o
s
θ
Limiting frictional friction is
f
l
=
μ
N
=
m
g
c
o
s
θ
, in the upward the plane direction.
Component of gravitational force in downward the plane direction is,
F
g
=
m
g
s
i
n
θ
A. when
θ
=
0
0
⟹
F
g
=
0
,
f
l
=
m
g
=
20
N
as,
F
g
<
f
l
, frictional force is zero.
B. when
θ
=
90
0
⟹
F
g
=
m
g
s
i
n
90
0
=
20
N
,
f
l
=
m
g
c
o
s
90
0
=
0
frictional force is zero.
C. when
θ
=
30
0
⟹
F
g
=
m
g
s
i
n
30
0
=
10
N
,
f
l
=
m
g
c
o
s
30
0
=
10
√
3
N
as,
F
g
<
f
l
, frictional force is
F
g
=
10
N
.
D. when
θ
=
60
0
⟹
F
g
=
m
g
s
i
n
60
0
=
10
√
3
,
f
l
=
m
g
c
o
s
60
0
=
10
N
as,
F
g
>
f
l
, frictional force is
f
l
=
10
N
.
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